Question on: JAMB Mathematics - 2024
If y varies directly as the square root of x and y = 3 when x = 16, calculate y when x = 64.
A
12
B
6
C
3
D
5
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Correct Option: B
The problem states that y varies directly as √x. Thus:
\( y = k \sqrt{x} \)
Given y = 3 when x = 16:
3 = k \sqrt{16} = 4k
k = \frac{3}{4}
Now, when x = 64:
y = \frac{3}{4} \sqrt{64} = \frac{3}{4} \times 8 = 6
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